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Showing posts from September, 2018

Weekly Reflection 9-28-18

Finding coterminal and reference angles: I will be able to find the coterminal and reference angles. One example of an Coterminal angle is: Find the coterminal angle 86 degrees. To find the angle all you need to do is add or subtract 360 degrees, 86+360= 446 degrees or 86-360 = -274 degrees One example of an Reference angle: Find the reference angle of 312 degrees.  To find the angle I would first need to find out what quadrant it falls into. 312 degrees falls into quadrant 4. 312 is close to 360 so I would just subtract 360 from 312 and get 48 degrees. Before I say this is my final answer I need to make sure it follows the 2 rules that the reference angle has, which is it has to be positive and less than 90 degrees and 48 degrees ticks both of those boxes so 48 degrees is the answer. One misconception I had was with negative degrees. I didn't know which way they would go on a circle. I figured out my misconception when Mrs. Burton clarified it to the class that negative d...

Weekly Reflection 9-21-18

Evaluating and Converting: I will be able to evaluate trigonometric expressions and convert between radians and degrees. One example of evaluating is: Find Cot 45 degrees. Cot is the inverse of tangent so 1/tan(45)= 1 One example of converting radians to degrees: Convert 3pi/4 into degrees. First I would need to multiply 3pi/4 by 180/pi. The pi's would cancel and I would end up with 3*180/4 ---> 135 degrees is the answer. One example of converting degrees to radians: Convert 160 degrees in radians.  First I would multiply 160 by pi/180. 160 pi/180. This is no the simplified form so I would need to divide the top and the bottom by 20 and the final answer is 8pi/9 One misconception I had was with which equation to use to convert from radians to degrees or degrees to radians. I figured out my misconception on my own I figured the pi would be in the numerator when going from degree to radian because radians have pi and the pi would be in the denominator when going from r...

Weekly Reflection 9-14-18

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Trigonometric Word Problems: I will be able to find trigonometric ratios of acute angles. One example of a trigonometric word problem is: A 15 foot ladder rests against a tree on level ground and forms a 75 degree angle of elevation. What is the height of the tree? What is the distance of the tree to the base of the ladder. The first step in solving this problem would be to go through and find any important information. I know that the ladder leaning against the tree forms a right angle so I will be using a trig ratio. The ladder is 15 feet long and is the hypotenuse so I have one length. The ground under the tree forms a 75 degree angle of elevation. This angle is across from the 90 degree angle. To solve this problem I need to find height and the base of the tree from the ladder. To find height I need to find the Sine (opposite over hypotenuse) 75 degrees = x/15. If I multiply 15 to both sides I can cross out the 15 in the denominator: 15(sin75)=x, x is approximately 14.49...

Weekly Reflection 9-7-18

Exponential Word Problems I will be able to use compound interest to solve exponential problems. One example of an Exponential word problem is: Find the accumulated amount of money after 5 years if $4,300 is invested at 6% per year compounded quarterly . Find the growth factor .  In order to solve this problem you have to find out the accumulated amount after (t) number of years, which in this problem is what we are supposed to find out, the principle (original amount) which is 4300 (P) , the nominal interest rate per year, which is 6% or .06 (r) , the number of periods or years (n) , which is 4 because the money is compounded quarterly which is 4 times a year, and the number of years (t) , which is 5. Then you plug these numbers into the compound interest formula. A=P(1+r/n)^n*t ------->  A=4300(1+.06/4)^4*5 --------->  A=5791.48 The accumulated amount after 5 years is approximately $5791.48. The growth factor is 1.015 One misconception I had...

Weekly Reflection 8-31-18

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Logarithmic Functions I will be able to convert between exponential and logarithmic equations. For example 8 the problem is given b^a=123. To change this into log form you have to look at the base which is b, so log base (b) is the first step. The next step would be to look at the number behind the = sign which in this problem is 123 this number would is known as the solution. The last step is to find the exponent which is a and put this behind the equal sign. So your final answer is log(b) 123=a One misconception I had was if the base and solution is the same you can cross them out and your answer would be the exponent. I understood my misconception when Mrs.Burton explained it to the class. EQ: Exponential and logarithmic functions are related because exponential functions are the inverse of logarithmic functions. To convert exponential to logarithmic Log(b)x=n : b^n=x. You have to take the base b and the solution n would turn into the exponential. then the x value would tur...

Weekly Reflection 8-24-18

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Exponential and Linear Functions I will be able to know the difference between linear and exponential functions. In one example we are given a table with x and y values In this table you can see that the graph is decreasing by a negative 3: 5-2=3, 2-(-1)= -1, -1-(-4)=-7. Because -3 is being added consecutively this is an linear function.  One misconception I had was when I was putting the exponential value in the correct form. Instead of putting the function in the f(x)=Ca^x format I did 2.5x +50. The answer was 50(5/2)^x. I over came this misconception when Mrs.Burton explained the correct answers to the class. EQ: To determine if the function is a linear or exponential function you have to look at the y values if they are going up or down by adding then it is a linear function. If it is going up or down by multiplying it is exponential, If it is not going up or down in an even order by multiplying or adding then it is neither linear or exponential.